Pattern:

ABC

ABCD

Solution

Note: Don't jump directly to the solution, try it out yourself first.

Approach:

1)Require minimum 2 nested loop

2)Outer loop is for row

3)Inner loop is for column

4)Print in inner loop

Explanation:

1)The pattern has 4 rows.

2)The first row contains A, the second row contains AB, the third row contains ABC, and so on.

We use two loops:

Outer loop for rows (from 1 to 4).

Inner loop to print characters from 'A' to the respective row number.

Video Solution

Java

public class Main {

public static void main(String[] args) {

int rows = 4; // Number of rows

// Outer loop for rows

for (int i = 1; i <= rows; i++) {

// Inner loop for characters

for (char ch = 'A'; ch < 'A' + i; ch++) {

System.out.print(ch);

}

System.out.println(); // Move to the next line after printing a row

}

C++

#include <iostream>
using namespace std;

int main() {
    int rows = 4;  // Number of rows

    // Outer loop for rows
    for (int i = 1; i <= rows; i++) {
        // Inner loop for characters
        for (char ch = 'A'; ch < 'A' + i; ch++) {
            cout << ch;
        }
        cout << endl;  // Move to the next line after printing a row
    }

    return 0;
}