Pattern:
10 9 8 7
6 5 4
3 2
1
Solution
Note: Don't jump directly to the solution, try it out yourself first.
Pattern Breakdown
The total number of rows is 4.
The pattern has 4 rows, and each row contains decreasing numbers starting from 10.
To print this pattern, we need two loops:
-->Outer loop for the rows.
-->Inner loop for the columns (printing numbers in each row).
1) In each iteration of the outer loop:
2) The inner loop prints decreasing numbers starting from the current start_value.
3) The number of elements printed in each row is determined by total_rows - row.
4) After printing a number, the start_value is decremented.
Video Solution
| Java |
public class Main { public static void main(String[] args) { int total_rows = 4; // Number of rows int start_value = 10; // Starting value for the first row // Outer loop for rows for (int row = 0; row < total_rows; row++) { // Inner loop for columns (printing decreasing numbers) for (int col = 0; col < total_rows - row; col++) { System.out.print(start_value + " "); start_value--; // Decrease the number for the next column } System.out.println(); // Move to the next line } } } |
| C++ |
#include <iostream> using namespace std; int main() { int total_rows = 4; // Number of rows int start_value = 10; // Starting value for the first row // Outer loop for rows for (int row = 0; row < total_rows; row++) { // Inner loop for columns (printing decreasing numbers) for (int col = 0; col < total_rows - row; col++) { cout << start_value << " "; start_value--; // Decrease the number for the next column } cout << endl; // Move to the next line } return 0; } |
| Python |
total_rows = 4 # Number of rows start_value = 10 # Starting value for the first row # Outer loop for rows for row in range(total_rows): # Inner loop for columns (printing decreasing numbers) for col in range(total_rows - row): print(start_value, end=" ") start_value -= 1 # Decrease the number for the next column print() # Move to the next line |
