Pattern:
*
**
***
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Solution
Note: Don't jump directly to the solution, try it out yourself first.
Pattern Breakdown
The pattern has 4 rows, and each row contains stars (*) in a decreasing number:
Row 0: 3 Space 1 stars
Row 1: 2 Space 2 stars
Row 2: 1 Space 3 stars
Row 3: 0 Space 4 starsKey observation:
The number of spaces decreases with each row, starting from 3 (for row 0) and going down to 0 (for row 3).
The number of stars increases with each row, starting from 1 star (for row 0) and going up to 4 stars (for row 3).First Inner Loop (Spaces):
The first inner loop prints the spaces before the stars in each row.
The number of spaces in each row is equal to total_rows - row - 1
Second Inner Loop (Stars):
The second inner loop prints the stars in each row.
The number of stars in each row is equal to row + 1
Video Solution
| Java |
public class Main { public static void main(String[] args) { int total_rows = 4; // Number of rows // Outer loop for rows for (int row = 0; row < total_rows; row++) { // Inner loop for spaces for (int space = 0; space < total_rows - row - 1; space++) { System.out.print(" "); } // Inner loop for stars for (int star = 0; star <= row; star++) { System.out.print("*"); } System.out.println(); // Move to the next line } } } |
| C++ |
#include <iostream> using namespace std; int main() { int total_rows = 4; // Number of rows // Outer loop for rows for (int row = 0; row < total_rows; row++) { // Inner loop for spaces for (int space = 0; space < total_rows - row - 1; space++) { cout << " "; } // Inner loop for stars for (int star = 0; star <= row; star++) { cout << "*"; } cout << endl; // Move to the next line } return 0; } |
| Python |
total_rows = 4 # Number of rows # Outer loop for rows for row in range(total_rows): # Inner loop for spaces for space in range(total_rows - row - 1): print(" ", end="") # Inner loop for stars for star in range(row + 1): print("*", end="") print() # Move to the next line |
