Pattern:
ABCD
ABC
AB
A
Solution
Note: Don't jump directly to the solution, try it out yourself first.
Pattern Breakdown
The total number of rows is 4.
The numbers in each row start from 'A' and decrease in count as we move downward:
- Row 1 → ABCD ( 4 characters)
- Row 2 → ABC(3 characters)
- Row 3 → AB (2 characters)
- Row 4 → A (1 character)
The outer loop runs from 0 to total_rows - 1.
The inner loop prints characters starting from 'A' up to total_rows - row characters.
Video Solution
| Java |
public class Main { public static void main(String[] args) { int total_rows = 4; // Number of rows // Outer loop for rows (starting from 0) for (int row = 0; row < total_rows; row++) { // Inner loop for columns (printing letters) for (int col = 0; col < total_rows - row; col++) { System.out.print((char) ('A' + col)); } System.out.println(); // Move to the next line } } } |
| C++ |
#include <iostream> using namespace std; int main() { int total_rows = 4; // Number of rows // Outer loop for rows (starting from 0) for (int row = 0; row < total_rows; row++) { // Inner loop for columns (printing letters) for (int col = 0; col < total_rows - row; col++) { cout << (char) ('A' + col); } cout << endl; // Move to the next line } return 0; } |
| Python |
total_rows = 4 # Number of rows # Outer loop for rows (starting from 0) for row in range(total_rows): # Inner loop for columns (printing letters) for col in range(total_rows - row): print(chr(65 + col), end="") # Convert 65 to 'A' print() # Move to the next line |
